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el-menu动态加载路由,菜单的解决方案

16 人参与  2023年04月06日 11:59  分类 : 《随便一记》  评论

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先看需要实现的效果

在这里插入图片描述
这里有一级也有二级菜单,注意二级菜单的父目录(”选项设置“点击不会跳转,只是展开目录),然后点击去详情页,需要跳到一个隐藏的路由,不在菜单展示的路由在这里插入图片描述
还有一点要注意,就是这里有两个router-view,整个页面是一个router-view,可以由LoginView和HomeView替换(当前看到的页面),而HomeView下又有一个router-view,需要用来展示部门,系统,超时,员工设置,不合格品列表和不合格品详情页。


以上的信息均需要在数据库的表中体现
先看看直接写在代码里需要哪些操作

const routes = [  {    path: '',    name: 'login',    component: LoginView,  }  ,  {    component: HomeView,    children: [      {        path: '/home',        name: '不合格品列表',        component: BelowStandard      },      {        path: '/product/:id',        name: '不合格品详情',        component: BelowStandardDetail      }    ]  },  {    component: HomeView,    name: '选项设置',    children: [      {        path: '/employee',        name: '员工设置',        component: EmployeeConfig,      },      {        path: '/department',        name: '部门设置',        component: DepartmentConfig      },      {        path: '/system',        name: '系统设置',        component: SystemConfig      },      {        path: '/warn',        name: '超时提醒',        component: WarmConfig      }    ]  },  {    component: HomeView,    children: [      {        path: '/statistics',        name: '统计',        component: DailyStatistics      }    ]  },  {    component: HomeView,    children: [      {        path: '/log',        name: '日志管理',        component: LogManager      }    ]  },]

这是路由,当要动态从数据库加载时,就不能写在这

<el-menu            router            active-text-color="#ffd04b"            background-color="#000"            class="el-menu-vertical-demo"            :default-active="this.$route.path"            text-color="#fff"            @open=""            @close=""        >          <el-menu-item index="/home">            <template #title>              不合格品列表            </template>          </el-menu-item>          <el-sub-menu index="/subMenuConfig">            <template #title>              选项设置            </template>            <el-menu-item index="/department">部门设置</el-menu-item>            <el-menu-item index="/system">系统设置</el-menu-item>            <el-menu-item index="/warn">超时设置</el-menu-item>            <el-menu-item index="/employee">员工设置</el-menu-item>          </el-sub-menu>          <el-menu-item index="/statistics">            <span>统计</span>          </el-menu-item>          <el-menu-item index="/log">            <span>日志管理</span>          </el-menu-item>        </el-menu>

这是el-menu开启了路由功能,所以能跳转路由,当动态加载的时候,这部分需要改造成v-for

数据库

在这里插入图片描述

说明:parent_id为0的即是一级目录,但是一级目录里一部分可以直接展示界面,一部分是展开二级目录,我这是以component字段为home/HomeView.vue来区分是展示二级目录。


现在开始写后端程序,返回菜单的json格式数据。
在这里插入图片描述

List<Menu> menuList = menuMapper.getMenuByUserId(UserUtils.getLoginUser().getId());//根据ParentId分组Map<Integer, List<Menu>> map = menuList.stream().collect(Collectors.groupingBy(Menu::getParentId, TreeMap::new,Collectors.toList()));List<Menu> menus = map.get(0);//一级菜单menus.forEach(menu->{//给有二级菜单的目录设置children属性    List<Menu> children = map.get(menu.getId());    menu.setChildren(children);});return menus;

从数据库查询到的数据格式如图,然后分一级二级菜单处理后,再返回前端

[{"name": "不合格品列表","path": "/home","component": "product/BelowStandard.vue","orderNum": 1,"parentId": 0,"isHidden": false,"children": null},{"name": "选项设置","path": "/subMenuConfig","component": "home/HomeView.vue","orderNum": 2,"parentId": 0,"isHidden": false,"children": [{"name": "员工设置","path": "/employee","component": "config/EmployeeConfig.vue","orderNum": 1,"parentId": 2,"isHidden": false,"children": null},{"name": "部门设置","path": "/department","component": "config/DepartmentConfig.vue","orderNum": 2,"parentId": 2,"isHidden": false,"children": null},{"name": "系统设置","path": "/system","component": "config/SystemConfig.vue","orderNum": 3,"parentId": 2,"isHidden": false,"children": null},{"name": "超时提醒","path": "/warn","component": "config/WarmConfig.vue","orderNum": 4,"parentId": 2,"isHidden": false,"children": null}]},{"name": "统计","path": "/statistics","component": "statistics/DailyStatistics.vue","orderNum": 3,"parentId": 0,"isHidden": false,"children": null},{"name": "日志管理","path": "/log","component": "log/LogManager.vue","orderNum": 4,"parentId": 0,"isHidden": false,"children": null},{"name": "不合格品详情","path": "/product/:id","component": "product/BelowStandardDetail.vue","orderNum": 5,"parentId": 0,"isHidden": true,"children": null}]

前端得到数据之后进行处理,再添加到路由,过程中遇到一个问题,vue-router4版本去掉addRoutes换成addRoute带来的问题困扰我很久,详情可以查看另一篇笔记:
第一次push路由不匹配

初始化路由:

router.beforeEach((to, from, next) => {//配置路由守卫    if(to.path==='/'){        next()    }else if(store.state.user.id){        initMenus(router,store,next,to)    }else{        next({ path: '/',query: {redirect: to.path}});    }});export const initMenus = (router, store,next,to) => {//按F5刷新的话vuex里的会被清空,长度变为0    if (store.state.menu !== null) {        next()    }else {        axios.get("/menu").then(response => {            if (response) {                let responseData = response.data                if (responseData.flag) {                    store.state.menu = responseData.data                    initRoute(router,store.state)                    next({...to,replace:true})//解决router4版本的第一次路由不匹配问题                } else {                    this.$ElMessage.error('请求菜单失败')                }            }        })    }}const initRoute = (router,state)=> {    const loadView = view => {//这种引入方式控制台不会报警告        // 路由懒加载        return () => import(`@/views/${view}`)    };    const menus = state.menu    const firstLevelMenu = {        children: [],        component: loadView('home/HomeView.vue')    }    menus.forEach(menu=>{        menu.component = loadView(menu.component)        if(menu.children === null || menu.children.length === 0){            firstLevelMenu.children.push(menu)        }else{            menu.children.forEach(children=>{                children.component = loadView(children.component)            })            router.addRoute(menu)        }    })    router.addRoute(firstLevelMenu)}

完成这些配置之后,路由就能动态加载了,然后取出vuex中存储的menu生成el-menu

vuex中菜单大致如图

<el-menu    router    active-text-color="#ffd04b"    background-color="#000"    class="el-menu-vertical-demo"    :default-active="this.$route.path"    text-color="#fff"    @open=""    @close="">  <template v-for="route of this.$store.state.menu">    <template v-if="route.children === null || route.children.length === 0"><!--一级菜单-->      <template v-if="!route.isHidden">        <el-menu-item :index = "route.path">          <span>{{route.name}}</span>        </el-menu-item>      </template>    </template>    <template v-else><!--二级菜单-->      <template v-if="!route.isHidden">        <el-sub-menu :index = "route.path">          <template #title>            <span>{{route.name}}</span>          </template>          <template v-for="children of route.children">            <template v-if="!children.isHidden">              <el-menu-item :index = "children.path">                <span>{{children.name}}</span>              </el-menu-item>            </template>          </template>        </el-sub-menu>      </template>    </template>  </template></el-menu>

实现效果展示
在这里插入图片描述
在这里插入图片描述


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