当前位置:首页 » 《资源分享》 » 正文

Python——贪吃蛇

27 人参与  2024年09月18日 08:41  分类 : 《资源分享》  评论

点击全文阅读


以下是一个简单的贪吃蛇游戏的Python代码示例:

import pygameimport timeimport random# 初始化 Pygamepygame.init()# 定义颜色BLACK = (0, 0, 0)WHITE = (255, 255, 255)RED = (255, 0, 0)GREEN = (0, 255, 0)BLUE = (0, 0, 255)# 设置屏幕尺寸screen_width = 800screen_height = 600screen = pygame.display.set_mode((screen_width, screen_height))pygame.display.set_caption("贪吃蛇游戏")# 游戏帧率clock = pygame.time.Clock()snake_block_size = 20# 字体设置font_style = pygame.font.SysFont(None, 50)score_font = pygame.font.SysFont(None, 35)def your_score(score):    value = score_font.render("Your Score: " + str(score), True, WHITE)    screen.blit(value, [0, 0])def our_snake(snake_block_size, snake_list):    for x in snake_list:        pygame.draw.rect(screen, GREEN, [x[0], x[1], snake_block_size, snake_block_size])# 游戏主循环def game_loop():    game_over = False    game_quit = False    x1 = screen_width / 2    y1 = screen_height / 2    x1_change = 0    y1_change = 0    snake_list = []    snake_length = 1    foodx = round(random.randrange(0, screen_width - snake_block_size) / 20.0) * 20.0    foody = round(random.randrange(0, screen_height - snake_block_size) / 20.0) * 20.0    while not game_quit:        while game_over == True:            screen.fill(BLACK)            message = font_style.render("Game Over! Press Q-Quit or C-Play Again", True, WHITE)            screen.blit(message, [screen_width / 6, screen_height / 3])            your_score(snake_length - 1)            pygame.display.update()            # 游戏结束等待用户输入            for event in pygame.event.get():                if event.type == pygame.QUIT:                    game_quit = True                    game_over = False                if event.type == pygame.KEYDOWN:                    if event.key == pygame.K_q:                        game_quit = True                        game_over = False                    if event.key == pygame.K_c:                        game_loop()        for event in pygame.event.get():            if event.type == pygame.QUIT:                game_quit = True            if event.type == pygame.KEYDOWN:                if event.key == pygame.K_LEFT:                    x1_change = -snake_block_size                    y1_change = 0                elif event.key == pygame.K_RIGHT:                    x1_change = snake_block_size                    y1_change = 0                elif event.key == pygame.K_UP:                    y1_change = -snake_block_size                    x1_change = 0                elif event.key == pygame.K_DOWN:                    y1_change = snake_block_size                    x1_change = 0        if x1 >= screen_width or x1 < 0 or y1 >= screen_height or y1 < 0:            game_over = True        x1 += x1_change        y1 += y1_change        screen.fill(BLACK)        pygame.draw.rect(screen, RED, [foodx, foody, snake_block_size, snake_block_size])        snake_head = []        snake_head.append(x1)        snake_head.append(y1)        snake_list.append(snake_head)        if len(snake_list) > snake_length:            del snake_list[0]        for x in snake_list[:-1]:            if x == snake_head:                game_over = True        our_snake(snake_block_size, snake_list)        your_score(snake_length - 1)        pygame.display.update()        if x1 == foodx and y1 == foody:            foodx = round(random.randrange(0, screen_width - snake_block_size) / 20.0) * 20.0            foody = round(random.randrange(0, screen_height - snake_block_size) / 20.0) * 20.0            snake_length += 1        clock.tick(10)    pygame.quit()    quit()game_loop()

这个代码使用Pygame库来创建一个简单的贪吃蛇游戏。在游戏中,玩家通过键盘控制贪吃蛇的移动方向,目标是吃到食物并尽可能多地增长长度。如果贪吃蛇碰到边界或自己的身体,游戏结束。游戏过程中会显示当前的分数。


点击全文阅读


本文链接:http://zhangshiyu.com/post/161066.html

<< 上一篇 下一篇 >>

  • 评论(0)
  • 赞助本站

◎欢迎参与讨论,请在这里发表您的看法、交流您的观点。

关于我们 | 我要投稿 | 免责申明

Copyright © 2020-2022 ZhangShiYu.com Rights Reserved.豫ICP备2022013469号-1