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C++:红黑树的深度剖析和模拟

11 人参与  2024年09月07日 09:27  分类 : 《资源分享》  评论

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文章目录

目录

文章目录

前言

一  红黑树的概念

二  红黑树的性质

三  红黑树节点的定义

四  红黑树结构

五  红黑树的插入操作

六  红黑树的验证 

七  红黑树的删除

八  红黑树与AVL树的比较 

九  红黑树的迭代器 

十  红黑树全代码

总结


前言

本篇详细介绍了进一步介绍C++中的红黑树,让使用者对红黑树有更加深刻的认知,而不是仅仅停留在表面,更好的模拟,为了更好的使用. 文章可能出现错误,如有请在评论区指正,让我们一起交流,共同进步!


一  红黑树的概念

        红黑树,是一种二叉搜索树,但在每个结点上增加一个存储位表示结点的颜色,可以是Red或 Black。 通过对任何一条从根到叶子的路径上各个结点着色方式的限制,红黑树确保没有一条路 径会比其他路径长出俩倍,因而是接近平衡的。

二  红黑树的性质

1. 每个结点不是红色就是黑色 

2. 根节点是黑色的 

3. 如果一个节点是红色的,则它的两个孩子结点是黑色的 

4. 对于每个结点,从该结点到其所有后代叶结点的简单路径上(根到NIP节点为一条路径),均包含相同数目的黑色结点 

5. 每个叶子结点都是黑色的(此处的叶子结点指的是空结点)

 

三  红黑树节点的定义

// 节点的颜色enum Color{RED, BLACK};// 红黑树节点的定义template<class T>struct RBTreeNode{     RBTreeNode(const ValueType& data = ValueType(),Color color = RED)         : _pLeft(nullptr), _pRight(nullptr), _pParent(nullptr)         , _data(data), _color(color)     {}     RBTreeNode<ValueType>* _pLeft;   // 节点的左孩子     RBTreeNode<ValueType>* _pRight;  // 节点的右孩子     RBTreeNode<ValueType>* _pParent; // 节点的双亲(红黑树需要旋转,为了实现简单给出该字段)     T _data;            // 节点的值域     Color _color;               // 节点的颜色};

四  红黑树结构

        为了后续实现关联式容器简单,红黑树的实现中增加一个头结点,因为跟节点必须为黑色,为了 与根节点进行区分,将头结点给成黑色,并且让头结点的 pParent 域指向红黑树的根节点,pLeft 域指向红黑树中最小的节点,_pRight域指向红黑树中最大的节点,如下:

五  红黑树的插入操作

 红黑树是在二叉搜索树的基础上加上其平衡限制条件,因此红黑树的插入可分为两步:

1. 按照二叉搜索的树规则插入新节点

2. 检测新节点插入后,红黑树的性质是否造到破坏 

因为新节点的默认颜色是红色(黑节点一定破坏规则4,因此:如果其双亲节点的颜色是黑色,没有违反红黑树任何性质则不需要调整;但当新插入节点的双亲节点颜色为红色时,就违反了性质三不能有连在一起的红色节点,此时需要对红黑树分情况来讨论: 

约定:cur为当前节点,p为父节点,g为祖父节点,u为叔叔节点 

        ⊚  情况一: cur为红,p为红,g为黑,u存在且为红

         ⊚  cur为红,p为红,g为黑,u不存在/u存在且为黑

         ⊚  情况三: cur为红,p为红,g为黑,u不存在/u存在且为黑(双旋转处理)

 插入代码如下:

bool Insert(const T& data){if (_root == nullptr){_root = new Node(data);_root->_col = BLACK;return true;}KeyOfT kot;Node* parent = nullptr;Node* cur = _root;while (cur){if (kot(cur->_data) < kot(data)){parent = cur;cur = cur->_right;}else if (kot(cur->_data) > kot(data)){parent = cur;cur = cur->_left;}else{return false;}}cur = new Node(data);// 新增节点。颜色红色给红色cur->_col = RED;if (kot(parent->_data) < kot(data)){parent->_right = cur;}else{parent->_left = cur;}cur->_parent = parent;while (parent && parent->_col == RED){Node* grandfather = parent->_parent;//    g//  p   uif (parent == grandfather->_left){Node* uncle = grandfather->_right;if (uncle && uncle->_col == RED){// u存在且为红 -》变色再继续往上处理parent->_col = uncle->_col = BLACK;grandfather->_col = RED;cur = grandfather;parent = cur->_parent;}else{// u存在且为黑或不存在 -》旋转+变色if (cur == parent->_left){//    g//  p   u//c//单旋RotateR(grandfather);parent->_col = BLACK;grandfather->_col = RED;}else{//    g//  p   u//    c//双旋RotateL(parent);RotateR(grandfather);cur->_col = BLACK;grandfather->_col = RED;}break;}}else{//    g//  u   pNode* uncle = grandfather->_left;// 叔叔存在且为红,-》变色即可if (uncle && uncle->_col == RED){parent->_col = uncle->_col = BLACK;grandfather->_col = RED;// 继续往上处理cur = grandfather;parent = cur->_parent;}else // 叔叔不存在,或者存在且为黑{// 情况二:叔叔不存在或者存在且为黑// 旋转+变色//      g//   u     p//            cif (cur == parent->_right){RotateL(grandfather);parent->_col = BLACK;grandfather->_col = RED;}else{//g//   u     p//      cRotateR(parent);RotateL(grandfather);cur->_col = BLACK;grandfather->_col = RED;}break;}}}_root->_col = BLACK;return true;}

六  红黑树的验证 

红黑树的检测分为两步:

        1. 检测其是否满足二叉搜索树(中序遍历是否为有序序列)

void _InOrder(Node* root){if (root == nullptr){return;}_InOrder(root->_left);cout << root->_kv.first << ":" << root->_kv.second << endl;_InOrder(root->_right);}

        2. 检测其是否满足红黑树的性质 

bool IsBalance(){    if (_root == nullptr)        return true;    if (_root->_col == RED) //检测根是否为黑色    {        cout << "异常:根为红色" << endl;        return false;    }     // 预先求出某条路径的黑色节点数量    size_t blackcount = 0;    Node *cur = _root;    while (cur)    {        if (cur->_col == BLACK)            blackcount++;        cur = cur->_left;    }     size_t k = 0; //作为参数传入,用于统计路径的黑色节点数量    return _IsBalance(_root, k, blackcount);} bool _IsBalance(Node *root, size_t k, size_t blackcount){    if (root == nullptr) //走到路径结尾    {        if (k != blackcount)        {            cout << "异常:路径黑节点数目不同" << endl;            return false;        }        return true;    }    if (root->_col == RED && root->_parent->_col == RED) //判断是否有连续红节点    {        cout << "异常:出现连续红节点" << endl;        return false;    }    if (root->_col == BLACK) //统计黑色节点数量        k++;     return _IsBalance(root->_left, k, blackcount)     && _IsBalance(root->_right, k, blackcount); //进行递归}

七  红黑树的删除

红黑树的删除本节不做讲解,参考《算法导论》或者《STL源码剖析》

红黑树 - _Never_ - 博客园 (cnblogs.com)

八  红黑树与AVL树的比较 

        红黑树和AVL树都是高效的平衡二叉树,增删改查的时间复杂度都是O($log_2 N$),红黑树不追 求绝对平衡,其只需保证最长路径不超过最短路径的2倍,相对而言,降低了插入和旋转的次数, 所以在经常进行增删的结构中性能比AVL树更优,而且红黑树实现比较简单,所以实际运用中红黑树更多。 

九  红黑树的迭代器 

        迭代器的好处是可以方便遍历,是数据结构的底层实现与用户透明。如果想要给红黑树增加迭代 器,需要考虑以前问题: 

        ⊚  begin()与end() :

        STL明确规定,begin()与end()代表的是一段前闭后开的区间,而对红黑树进行中序遍历后, 可以得到一个有序的序列,因此:begin()可以放在红黑树中最小节点(即最左侧节点)的位置,end()放在最大节点(最右侧节点)的下一个位置,关键是最大节点的下一个位置在哪块? 能否给成nullptr呢?答案是行不通的,因为对end()位置的迭代器进行--操作,必须要能找最后一个元素,此处就不行,因此最好的方式是将end()放在头结点的位置

        ⊚  operator++()与operator--() 

 operator++():

//typedef RBTreeIterator<T> Self;Self& operator++(){if (_node->_right){// 右不为空,右子树最左节点就是中序下一个Node* leftMost = _node->_right;while (leftMost->_left){leftMost = leftMost->_left;}_node = leftMost;}else{Node* cur = _node;Node* parent = cur->_parent;while (parent && cur == parent->_right){cur = parent;parent = cur->_parent;}_node = parent;}return *this;}

  operator--():

Self& operator--(){//分三种情况讨论:_pNode 在head的位置,_pNode 左子树存在,_pNode 左子树不//存在// 1. _pNode 在head的位置,--应该将_pNode放在红黑树中最大节点的位置if (_node->_parent->_parent == _node && _node->_col == RED)_node = _node->_right;else if (_node->_left){// 2. _pNode的左子树存在,在左子树中找最大的节点,即左子树中最右侧节点_node = _node->_left;while (_node->_right)_node = _node->_right;}else{// _pNode的左子树不存在,只能向上找Node pParent = _node->_parent;while (_node == pParent->_left){_node = pParent;pParent = _node->_parent;}_node = pParent;}}

迭代器全代码:

template<class T>struct RBTreeIterator{typedef RBTreeNode<T> Node;typedef RBTreeIterator<T> Self;Node* _node;RBTreeIterator(Node* node):_node(node){}Self& operator++(){if (_node->_right){// 右不为空,右子树最左节点就是中序下一个Node* leftMost = _node->_right;while (leftMost->_left){leftMost = leftMost->_left;}_node = leftMost;}else{Node* cur = _node;Node* parent = cur->_parent;while (parent && cur == parent->_right){cur = parent;parent = cur->_parent;}_node = parent;}return *this;}Self& operator--(){//分三种情况讨论:_pNode 在head的位置,_pNode 左子树存在,_pNode 左子树不//存在// 1. _pNode 在head的位置,--应该将_pNode放在红黑树中最大节点的位置if (_node->_parent->_parent == _node && _node->_col == RED)_node = _node->_right;else if (_node->_left){// 2. _pNode的左子树存在,在左子树中找最大的节点,即左子树中最右侧节点_node = _node->_left;while (_node->_right)_node = _node->_right;}else{// _pNode的左子树不存在,只能向上找Node pParent = _node->_parent;while (_node == pParent->_left){_node = pParent;pParent = _node->_parent;}_node = pParent;}}T& operator*(){return _node->_data;}bool operator!= (const Self& s){return _node != s._node;}};

十  红黑树全代码

#pragma once#include<iostream>#include<vector>#include<assert.h>using namespace std;enum Colour{RED,BLACK};template<class T>struct RBTreeNode{T _data;RBTreeNode<T>* _left;RBTreeNode<T>* _right;RBTreeNode<T>* _parent;Colour _col;RBTreeNode(const T& data): _data(data), _left(nullptr), _right(nullptr), _parent(nullptr){}};template<class T>struct RBTreeIterator{typedef RBTreeNode<T> Node;typedef RBTreeIterator<T> Self;Node* _node;RBTreeIterator(Node* node):_node(node){}Self& operator++(){if (_node->_right){// 右不为空,右子树最左节点就是中序下一个Node* leftMost = _node->_right;while (leftMost->_left){leftMost = leftMost->_left;}_node = leftMost;}else{Node* cur = _node;Node* parent = cur->_parent;while (parent && cur == parent->_right){cur = parent;parent = cur->_parent;}_node = parent;}return *this;}Self& operator--(){//分三种情况讨论:_pNode 在head的位置,_pNode 左子树存在,_pNode 左子树不//存在// 1. _pNode 在head的位置,--应该将_pNode放在红黑树中最大节点的位置if (_node->_parent->_parent == _node && _node->_col == RED)_node = _node->_right;else if (_node->_left){// 2. _pNode的左子树存在,在左子树中找最大的节点,即左子树中最右侧节点_node = _node->_left;while (_node->_right)_node = _node->_right;}else{// _pNode的左子树不存在,只能向上找Node pParent = _node->_parent;while (_node == pParent->_left){_node = pParent;pParent = _node->_parent;}_node = pParent;}}T& operator*(){return _node->_data;}bool operator!= (const Self& s){return _node != s._node;}};template<class K, class T, class KeyOfT>class RBTree{typedef RBTreeNode<T> Node;public:typedef RBTreeIterator<T> Iterator;Iterator Begin(){Node* leftMost = _root;while (leftMost && leftMost->_left){leftMost = leftMost->_left;}return Iterator(leftMost);}Iterator End(){return Iterator(nullptr);}RBTree() = default;RBTree(const RBTree& t){_root = Copy(t._root);}RBTree& operator=(RBTree t){swap(_root, t._root);return *this;}~RBTree(){Destroy(_root);_root = nullptr;}bool Insert(const T& data){if (_root == nullptr){_root = new Node(data);_root->_col = BLACK;return true;}KeyOfT kot;Node* parent = nullptr;Node* cur = _root;while (cur){if (kot(cur->_data) < kot(data)){parent = cur;cur = cur->_right;}else if (kot(cur->_data) > kot(data)){parent = cur;cur = cur->_left;}else{return false;}}cur = new Node(data);// 新增节点。颜色红色给红色cur->_col = RED;if (kot(parent->_data) < kot(data)){parent->_right = cur;}else{parent->_left = cur;}cur->_parent = parent;while (parent && parent->_col == RED){Node* grandfather = parent->_parent;//    g//  p   uif (parent == grandfather->_left){Node* uncle = grandfather->_right;if (uncle && uncle->_col == RED){// u存在且为红 -》变色再继续往上处理parent->_col = uncle->_col = BLACK;grandfather->_col = RED;cur = grandfather;parent = cur->_parent;}else{// u存在且为黑或不存在 -》旋转+变色if (cur == parent->_left){//    g//  p   u//c//单旋RotateR(grandfather);parent->_col = BLACK;grandfather->_col = RED;}else{//    g//  p   u//    c//双旋RotateL(parent);RotateR(grandfather);cur->_col = BLACK;grandfather->_col = RED;}break;}}else{//    g//  u   pNode* uncle = grandfather->_left;// 叔叔存在且为红,-》变色即可if (uncle && uncle->_col == RED){parent->_col = uncle->_col = BLACK;grandfather->_col = RED;// 继续往上处理cur = grandfather;parent = cur->_parent;}else // 叔叔不存在,或者存在且为黑{// 情况二:叔叔不存在或者存在且为黑// 旋转+变色//      g//   u     p//            cif (cur == parent->_right){RotateL(grandfather);parent->_col = BLACK;grandfather->_col = RED;}else{//g//   u     p//      cRotateR(parent);RotateL(grandfather);cur->_col = BLACK;grandfather->_col = RED;}break;}}}_root->_col = BLACK;return true;}void InOrder(){_InOrder(_root);cout << endl;}int Height(){return _Height(_root);}int Size(){return _Size(_root);}bool IsBalance(){if (_root == nullptr)return true;if (_root->_col == RED){return false;}// 参考值int refNum = 0;Node* cur = _root;while (cur){if (cur->_col == BLACK){++refNum;}cur = cur->_left;}return Check(_root, 0, refNum);}Node* Find(const K& key){Node* cur = _root;while (cur){if (cur->_kv.first < key){cur = cur->_right;}else if (cur->_kv.first > key){cur = cur->_left;}else{return cur;}}return nullptr;}private:bool Check(Node* root, int blackNum, const int refNum){if (root == nullptr){//cout << blackNum << endl;if (refNum != blackNum){cout << "存在黑色节点的数量不相等的路径" << endl;return false;}return true;}if (root->_col == RED && root->_parent->_col == RED){cout << root->_kv.first << "存在连续的红色节点" << endl;return false;}if (root->_col == BLACK){blackNum++;}return Check(root->_left, blackNum, refNum)&& Check(root->_right, blackNum, refNum);}int _Size(Node* root){return root == nullptr ? 0 : _Size(root->_left) + _Size(root->_right) + 1;}int _Height(Node* root){if (root == nullptr)return 0;int leftHeight = _Height(root->_left);int rightHeight = _Height(root->_right);return leftHeight > rightHeight ? leftHeight + 1 : rightHeight + 1;}void _InOrder(Node* root){if (root == nullptr){return;}_InOrder(root->_left);cout << root->_kv.first << ":" << root->_kv.second << endl;_InOrder(root->_right);}void RotateL(Node* parent){_rotateNum++;Node* subR = parent->_right;Node* subRL = subR->_left;parent->_right = subRL;if (subRL)subRL->_parent = parent;Node* parentParent = parent->_parent;subR->_left = parent;parent->_parent = subR;if (parentParent == nullptr){_root = subR;subR->_parent = nullptr;}else{if (parent == parentParent->_left){parentParent->_left = subR;}else{parentParent->_right = subR;}subR->_parent = parentParent;}}void  RotateR(Node* parent){_rotateNum++;Node* subL = parent->_left;Node* subLR = subL->_right;parent->_left = subLR;if (subLR)subLR->_parent = parent;Node* parentParent = parent->_parent;subL->_right = parent;parent->_parent = subL;if (parentParent == nullptr){_root = subL;subL->_parent = nullptr;}else{if (parent == parentParent->_left){parentParent->_left = subL;}else{parentParent->_right = subL;}subL->_parent = parentParent;}}void Destroy(Node* root){if (root == nullptr)return;Destroy(root->_left);Destroy(root->_right);delete root;}Node* Copy(Node* root){if (root == nullptr)return nullptr;Node* newRoot = new Node(root->_kv);newRoot->_left = Copy(root->_left);newRoot->_right = Copy(root->_right);return newRoot;}private:Node* _root = nullptr;public:int _rotateNum = 0; //旋转次数};

总结

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